The problem is to solve the equation $12x^3 = 3x^2$ for $x$.

AlgebraPolynomial EquationsCubic EquationsFactoringSolving Equations
2025/5/1

1. Problem Description

The problem is to solve the equation 12x3=3x212x^3 = 3x^2 for xx.

2. Solution Steps

To solve the equation 12x3=3x212x^3 = 3x^2, we first rearrange the equation to get all terms on one side:
12x33x2=012x^3 - 3x^2 = 0
Next, we factor out the greatest common factor, which is 3x23x^2:
3x2(4x1)=03x^2(4x - 1) = 0
Now, we set each factor equal to zero and solve for xx.
3x2=03x^2 = 0 or 4x1=04x - 1 = 0
From 3x2=03x^2 = 0, we get x2=0x^2 = 0, which implies x=0x = 0.
From 4x1=04x - 1 = 0, we get 4x=14x = 1, which implies x=14x = \frac{1}{4}.
Thus, the solutions for xx are 00 and 14\frac{1}{4}.

3. Final Answer

x=0,14x = 0, \frac{1}{4}

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