The problem asks us to find the slope and y-intercept of a given line, and then write the equation of the line in slope-intercept form ($y = mx + b$). The graph shows that the line passes through the points (0, 10) and (10, 0).

1. Problem Description

The problem asks us to find the slope and y-intercept of a given line, and then write the equation of the line in slope-intercept form ($y = mx + b$). The graph shows that the line passes through the points (0, 10) and (10, 0).

2. Solution Steps

First, we find the slope $m$ using the two given points $(x_1, y_1) = (0, 10)$ and $(x_2, y_2) = (10, 0)$.

The formula for the slope is:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 10}{10 - 0} = \frac{-10}{10} = -1$

The y-intercept $b$ is the y-coordinate of the point where the line crosses the y-axis. From the graph, we can see that the y-intercept is

1

0. So, $b = 10$.

Now, we write the equation of the line in slope-intercept form:

$y = mx + b$

Substituting $m = -1$ and $b = 10$, we get:

$y = -1x + 10$

$y = -x + 10$

3. Final Answer

$y = -x + 10$