The problem asks us to solve for $x$ in the equation $\ln(2x+5) = 2.3$ by writing the equation in exponential form and rounding the answer to three decimal places.

AlgebraLogarithmsExponential EquationsSolving EquationsApproximation
2025/5/2

1. Problem Description

The problem asks us to solve for xx in the equation ln(2x+5)=2.3\ln(2x+5) = 2.3 by writing the equation in exponential form and rounding the answer to three decimal places.

2. Solution Steps

We start with the given equation:
ln(2x+5)=2.3\ln(2x+5) = 2.3
Since ln\ln is the natural logarithm (base ee), we can rewrite the equation in exponential form:
e2.3=2x+5e^{2.3} = 2x+5
Now we solve for xx:
e2.39.974182455e^{2.3} \approx 9.974182455
9.974182455=2x+59.974182455 = 2x + 5
9.9741824555=2x9.974182455 - 5 = 2x
4.974182455=2x4.974182455 = 2x
x=4.9741824552x = \frac{4.974182455}{2}
x2.487091228x \approx 2.487091228
Rounding to three decimal places, we get x2.487x \approx 2.487.

3. Final Answer

x=2.487x = 2.487

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