The problem asks us to solve the equation $8 + \log(16x) = 36 - 3\log(x)$ for $x$.

AlgebraLogarithmsEquationsLogarithmic PropertiesSolving Equations
2025/5/2

1. Problem Description

The problem asks us to solve the equation 8+log(16x)=363log(x)8 + \log(16x) = 36 - 3\log(x) for xx.

2. Solution Steps

We are given the equation 8+log(16x)=363log(x)8 + \log(16x) = 36 - 3\log(x).
Subtracting 8 from both sides gives
log(16x)=283log(x)\log(16x) = 28 - 3\log(x).
We can use the property log(ab)=log(a)+log(b)\log(ab) = \log(a) + \log(b) to rewrite log(16x)\log(16x) as log(16)+log(x)\log(16) + \log(x).
So, we have log(16)+log(x)=283log(x)\log(16) + \log(x) = 28 - 3\log(x).
Adding 3log(x)3\log(x) to both sides yields
log(16)+4log(x)=28\log(16) + 4\log(x) = 28.
Subtracting log(16)\log(16) from both sides, we have
4log(x)=28log(16)4\log(x) = 28 - \log(16).
Dividing by 4 gives
log(x)=714log(16)\log(x) = 7 - \frac{1}{4}\log(16).
Using the power rule of logarithms, log(ab)=blog(a)\log(a^b) = b\log(a), we can rewrite the equation as:
log(x)=7log(161/4)\log(x) = 7 - \log(16^{1/4}).
Since 161/4=164=216^{1/4} = \sqrt[4]{16} = 2, we have
log(x)=7log(2)\log(x) = 7 - \log(2).
Then log(x)=log(107)log(2)\log(x) = \log(10^7) - \log(2), assuming base 10 logarithm.
Using the property log(a)log(b)=log(ab)\log(a) - \log(b) = \log(\frac{a}{b}), we get
log(x)=log(1072)=log(100000002)=log(5000000)\log(x) = \log(\frac{10^7}{2}) = \log(\frac{10000000}{2}) = \log(5000000).
Therefore, x=5000000x = 5000000.

3. Final Answer

x=5000000x = 5000000

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