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A snail starts at corner A of a regular pentagon and crawls clockwise a distance of $\frac{13}{20}$ of the total distance around the pentagon. We want to determine which side of the pentagon the snail will be on.

GeometryGeometryPerimeterPentagonFractionsClockwise Movement
2025/5/3

1. Problem Description

A snail starts at corner A of a regular pentagon and crawls clockwise a distance of 1320\frac{13}{20} of the total distance around the pentagon. We want to determine which side of the pentagon the snail will be on.

2. Solution Steps

A regular pentagon has 5 sides of equal length.
The snail crawls 1320\frac{13}{20} of the perimeter. Since there are 5 sides, we can divide the fraction 1320\frac{13}{20} by 15\frac{1}{5} to find out how many sides the snail traverses. Or, equivalently, multiply 1320\frac{13}{20} by 5 to determine how many sides of the pentagon the snail travels.
1320×5=13×520=6520=134=314 \frac{13}{20} \times 5 = \frac{13 \times 5}{20} = \frac{65}{20} = \frac{13}{4} = 3\frac{1}{4}
The snail crawls 3143\frac{1}{4} sides. Starting at corner A, the snail crawls along side AB, then side BC, then side CD. Then the snail travels 14\frac{1}{4} of the length of side DE. So the snail will be on side DE.

3. Final Answer

(D) DE

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