A tank is emptied using a pump. The emptying operation lasts 50 minutes. We need to calculate the flow rate. We're given that the volume of the tank is emptied in 50 minutes and the question asks to determine the flow rate (debit). It seems the problem is missing information about the volume of the tank. However, if we assume the problem asks to calculate the flow rate if the volume (contenance) is $V$, we can provide a generalized answer.

Applied MathematicsRate of ChangeFlow RateVolumeUnits ConversionProblem Solving
2025/5/6

1. Problem Description

A tank is emptied using a pump. The emptying operation lasts 50 minutes. We need to calculate the flow rate. We're given that the volume of the tank is emptied in 50 minutes and the question asks to determine the flow rate (debit). It seems the problem is missing information about the volume of the tank. However, if we assume the problem asks to calculate the flow rate if the volume (contenance) is VV, we can provide a generalized answer.

2. Solution Steps

Let VV be the volume of the tank. The operation takes 50 minutes.
We want to find the flow rate, which is volume per unit time.
Flow rate = VolumeTime\frac{Volume}{Time}.
Time is 50 minutes. We can convert this to hours by dividing by 60:
Time=5060=56Time = \frac{50}{60} = \frac{5}{6} hours.
Flow rate = V56=6V5\frac{V}{\frac{5}{6}} = \frac{6V}{5}.
Therefore, if V is in liters, the flow rate is in liters/hour. If V is in m3m^3, the flow rate is in m3m^3/hour. If V is in gallons, the flow rate is in gallons/hour.
If we assume the units are litres and we leave the time in minutes, the flow rate is V50\frac{V}{50} litres/minute.

3. Final Answer

If VV is the volume of the tank in liters, the flow rate is V50\frac{V}{50} liters/minute or 6V5\frac{6V}{5} liters/hour. Without knowing the volume V, we can only give the flow rate as a function of V.

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