We are given a quadrilateral QRST inscribed in a circle U. The angles are given as $Q = 79^\circ$, $R = 67^\circ$, $T = (x+96)^\circ$, and $S = (2y+17)^\circ$. We need to find the values of $x$ and $y$.

GeometryCircleQuadrilateralInscribedAnglesSupplementary AnglesAlgebra
2025/5/6

1. Problem Description

We are given a quadrilateral QRST inscribed in a circle U. The angles are given as Q=79Q = 79^\circ, R=67R = 67^\circ, T=(x+96)T = (x+96)^\circ, and S=(2y+17)S = (2y+17)^\circ. We need to find the values of xx and yy.

2. Solution Steps

Since the quadrilateral QRST is inscribed in a circle, opposite angles are supplementary. This means that the sum of opposite angles is 180180^\circ.
Therefore, we have:
Q+S=180Q + S = 180^\circ
R+T=180R + T = 180^\circ
Using the given values, we can write the equations as:
79+(2y+17)=18079 + (2y+17) = 180
67+(x+96)=18067 + (x+96) = 180
Solving for yy in the first equation:
79+2y+17=18079 + 2y + 17 = 180
96+2y=18096 + 2y = 180
2y=180962y = 180 - 96
2y=842y = 84
y=842y = \frac{84}{2}
y=42y = 42
Solving for xx in the second equation:
67+x+96=18067 + x + 96 = 180
x+163=180x + 163 = 180
x=180163x = 180 - 163
x=17x = 17

3. Final Answer

x=17x = 17
y=42y = 42

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