The problem asks us to graph a circle with center $(-3, 0)$ and radius $3$.

1. Problem Description

The problem asks us to graph a circle with center $(-3, 0)$ and radius $3$.

2. Solution Steps

The equation of a circle with center $(h, k)$ and radius $r$ is given by:

$(x - h)^2 + (y - k)^2 = r^2$

In our case, the center is $(h, k) = (-3, 0)$ and the radius is $r = 3$. Plugging these values into the equation of a circle, we get:

$(x - (-3))^2 + (y - 0)^2 = 3^2$

$(x + 3)^2 + y^2 = 9$

To graph the circle, first plot the center at $(-3, 0)$. Then, from the center, move 3 units to the right, 3 units to the left, 3 units up, and 3 units down. These points will be on the circle. Specifically, the points are:

- Right: $(-3 + 3, 0) = (0, 0)$

- Left: $(-3 - 3, 0) = (-6, 0)$

- Up: $(-3, 0 + 3) = (-3, 3)$

- Down: $(-3, 0 - 3) = (-3, -3)$

Connect these points with a smooth curve to form the circle.

3. Final Answer

The circle with center $(-3, 0)$ and radius $3$ is graphed as described above. It passes through the points $(0, 0)$, $(-6, 0)$, $(-3, 3)$, and $(-3, -3)$.