The problem seems to involve finding the area of triangle $ABC$. The given information appears to be $A = \frac{h \times b}{2}$ and $A = \frac{a \times \sqrt{3} \times a}{2}$, where $A$ represents the area, $h$ represents height, $b$ represents base and $a$ is a length associated with the triangle. It asks for the area of the triangle.

1. Problem Description

The problem seems to involve finding the area of triangle $ABC$. The given information appears to be $A = \frac{h \times b}{2}$ and $A = \frac{a \times \sqrt{3} \times a}{2}$, where $A$ represents the area, $h$ represents height, $b$ represents base and $a$ is a length associated with the triangle. It asks for the area of the triangle.

2. Solution Steps

The area of a triangle is given by:

$Area = \frac{1}{2} \times base \times height$

From the image, it seems like they are trying to compute the area of triangle $ABC$. The handwriting indicates that the area is also given by

$Area = \frac{a \times \sqrt{3} \times a}{2} = \frac{a^2 \sqrt{3}}{2}$.

It appears the height, $h = a$ and the base, $b = a \sqrt{3}$. Then, we have

$Area = \frac{1}{2} \times a \times a\sqrt{3} = \frac{a^2\sqrt{3}}{2}$

3. Final Answer

The area of triangle $ABC$ is $\frac{a^2\sqrt{3}}{2}$.