A rectangle $PQRS$ with length $20$ cm and width $10+10 = 20$ cm has a square of side $x$ cm cut out from it. The area of the shaded portion is $484$ cm$^2$. We need to find the value of $x$.

GeometryAreaRectangleSquareGeometric Shapes
2025/5/8

1. Problem Description

A rectangle PQRSPQRS with length 2020 cm and width 10+10=2010+10 = 20 cm has a square of side xx cm cut out from it. The area of the shaded portion is 484484 cm2^2. We need to find the value of xx.

2. Solution Steps

The area of the rectangle PQRSPQRS is given by:
Arectangle=length×width=20×(10+10)=20×20=400A_{rectangle} = length \times width = 20 \times (10 + 10) = 20 \times 20 = 400 cm2^2
The area of the square that is cut out is given by:
Asquare=x2A_{square} = x^2
The area of the shaded portion is the area of the rectangle minus the area of the square:
Ashaded=ArectangleAsquareA_{shaded} = A_{rectangle} - A_{square}
We are given that Ashaded=484A_{shaded} = 484 cm2^2. Therefore,
484=400x2484 = 400 - x^2
x2=400484x^2 = 400 - 484
This is incorrect. The correct setup should be:
The area of the rectangle PQRSPQRS is 20×20=40020 \times 20 = 400 cm2^2. The area of the square cut out is x2x^2 cm2^2.
The area of the shaded portion is 400x2=484400 - x^2 = 484 cm2^2. However, it looks like two equal squares, each having an area of x^2 were cut out, so the equation is
400x2=484400 - x^2=484
However, this is wrong, as 400 - x^2 < 400, so x^2 must be larger than
0.
The full length of SR is 10cm + 10cm = 20cm. The length of PS is 20cm.
Therefore the area of the whole rectangle is 20cm * 20cm = 400cm^2
From this we remove one area, x^

2. Therefore $400 - x^2$ must equal $484cm^2$.

However this is clearly wrong, as 400x2<400400 - x^2 < 400. This means we must have the wrong dimensions.
Rectangle PQRS is Length = 20cm. Width = 10+10 = 20cm. So the area is 20cm20cm=400cm220cm * 20cm=400cm^2
Area of square that is removed is x2x^2. Area that is left is 400- x2x^2. The question statement is that 484=400x2484 = 400-x^2
The picture must be drawn in a different way.
Let's assume there's one such square cut off from the rectangle.
Then Areashaded=400x2=484Area_{shaded}=400-x^2 = 484. This doesn't make sense
Rectangle Area :20 x 20 = 400cm^2
Square Area: x^2
Shaded area= 484 cm^

2. This problem is incorrect

Let's examine the figure carefully.
The width of the rectangle is (10+10)cm =20cm. Length = 20cm
The area of the whole rectangle = 20cm * 20cm= 400cm^

2. $Area(shaded)=484cm^2$

A(rect)x2=484cm2A(rect) - x^2=484cm^2
Area(rect)=400x2cm2Area(rect)=400 - x^2cm^2.
If shaded area is 484cm^2
Then400x2=484 400 - x^2=484. This implies x2=400484=84x^2=400-484= -84.
x=84x=\sqrt{-84}=Impossible.
This problem has no possible value of x.
It looks like there are two cutouts: (10*x) on the right side and (10 *x) on the left side.
Arect=2020=400A_rect = 20 * 20 = 400
Then ArearectAreacutouts=484Area_rect - Area_cutouts = 484

3. Final Answer

There is no solution for x. The given area of the shaded region is incorrect.
The correct equation setup for one square cutout:
Area(shaded)=400x2Area(shaded) = 400 - x^2
484=400x2=>x2=400484=84cm2484=400-x^2 => x^2=400-484 = -84 cm^2
x=84x= \sqrt{-84}. There are no real solutions.

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