The problem asks to identify the center and radius of the circle given by the equation $(x+3)^2 + y^2 = 9$.

1. Problem Description

The problem asks to identify the center and radius of the circle given by the equation $(x+3)^2 + y^2 = 9$.

2. Solution Steps

The general equation of a circle with center $(h, k)$ and radius $r$ is:

$(x - h)^2 + (y - k)^2 = r^2$

Comparing the given equation $(x+3)^2 + y^2 = 9$ with the general equation, we can rewrite the given equation as:

$(x - (-3))^2 + (y - 0)^2 = 3^2$

Thus, we have $h = -3$, $k = 0$, and $r = 3$. Therefore, the center of the circle is $(-3, 0)$ and the radius is $3$.

3. Final Answer

Center: $(-3, 0)$

Radius: $3$