The problem is to evaluate the expression $5(33) + 2x = 1$. The variable $x$ has been crossed out. Thus, we are to evaluate $5 \times 33 + 2 \times something = 1$. Since the $x$ is crossed out, the intention may be to solve for $x$. Since it is crossed out, and equal to 1, let's assume it is supposed to be an incomplete equation where the second term $2x$ should be solved to equal 1. So $2x = 1$.

AlgebraLinear EquationsEquation SolvingArithmetic Operations
2025/5/6

1. Problem Description

The problem is to evaluate the expression 5(33)+2x=15(33) + 2x = 1. The variable xx has been crossed out. Thus, we are to evaluate 5×33+2×something=15 \times 33 + 2 \times something = 1. Since the xx is crossed out, the intention may be to solve for xx. Since it is crossed out, and equal to 1, let's assume it is supposed to be an incomplete equation where the second term 2x2x should be solved to equal

1. So $2x = 1$.

2. Solution Steps

Let's first calculate 5×335 \times 33:
5×33=1655 \times 33 = 165
Now, the equation becomes:
165+2x=1165 + 2x = 1
Subtract 165 from both sides of the equation:
2x=11652x = 1 - 165
2x=1642x = -164
Divide both sides by 2:
x=1642x = \frac{-164}{2}
x=82x = -82
Therefore the problem is 5(33)+2(82)=15(33) + 2(-82) = 1, which evaluates to
165+(164)=1165 + (-164) = 1, so 1=11 = 1.

3. Final Answer

x=82x = -82

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