The problem is to expand the given function $f(x)=(2x^4 - 3)(x^2 + 1)$.

AlgebraPolynomial ExpansionAlgebraic Manipulation
2025/5/8

1. Problem Description

The problem is to expand the given function f(x)=(2x43)(x2+1)f(x)=(2x^4 - 3)(x^2 + 1).

2. Solution Steps

We need to expand the given expression by multiplying each term in the first parenthesis with each term in the second parenthesis.
f(x)=(2x43)(x2+1)f(x) = (2x^4 - 3)(x^2 + 1)
f(x)=2x4(x2+1)3(x2+1)f(x) = 2x^4(x^2 + 1) - 3(x^2 + 1)
f(x)=2x4(x2)+2x4(1)3(x2)3(1)f(x) = 2x^4(x^2) + 2x^4(1) - 3(x^2) - 3(1)
Using the rule xaxb=xa+bx^a \cdot x^b = x^{a+b}, we have:
2x4(x2)=2x4+2=2x62x^4(x^2) = 2x^{4+2} = 2x^6
Substituting this back into the equation:
f(x)=2x6+2x43x23f(x) = 2x^6 + 2x^4 - 3x^2 - 3

3. Final Answer

f(x)=2x6+2x43x23f(x) = 2x^6 + 2x^4 - 3x^2 - 3

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