The problem shows the chemical formula of lead(II) nitrate: $Pb(NO_3)_2$. The question requires calculating the molar mass of this compound.

1. Problem Description

The problem shows the chemical formula of lead(II) nitrate: $Pb(NO_3)_2$. The question requires calculating the molar mass of this compound.

2. Solution Steps

To calculate the molar mass of $Pb(NO_3)_2$, we need the atomic masses of each element:

- Lead (Pb): 207.2 g/mol

- Nitrogen (N): 14.01 g/mol

- Oxygen (O): 16.00 g/mol

The formula $Pb(NO_3)_2$ means there is:

- 1 atom of Pb

- 2 atoms of N

- 6 atoms of O

Molar mass of $Pb(NO_3)_2$ = (1 * Molar mass of Pb) + (2 * Molar mass of N) + (6 * Molar mass of O)

Molar mass of $Pb(NO_3)_2$ = (1 * 207.2) + (2 * 14.01) + (6 * 16.00)

Molar mass of $Pb(NO_3)_2$ = 207.2 + 28.02 + 96.00

Molar mass of $Pb(NO_3)_2$ = 331.22 g/mol

3. Final Answer

The molar mass of $Pb(NO_3)_2$ is 331.22 g/mol.