The problem asks to find the indicated measures in three different circle diagrams. a) Find $m\angle 1$ given that $m\stackrel{\frown}{DB} = 82^{\circ}$ and $m\stackrel{\frown}{AC} = 71^{\circ}$. b) Find $m\stackrel{\frown}{UW}$ given that $m\angle V = 26^{\circ}$ and $m\angle UTV = 36^{\circ}$. c) Find $m\angle P$ given that $m\stackrel{\frown}{KL} = 52^{\circ}$ and $m\stackrel{\frown}{JN} = 18^{\circ}$.

GeometryCircle GeometryAngles in CirclesArcsInscribed AnglesCentral AnglesSecantsChords
2025/5/9

1. Problem Description

The problem asks to find the indicated measures in three different circle diagrams.
a) Find m1m\angle 1 given that mDB=82m\stackrel{\frown}{DB} = 82^{\circ} and mAC=71m\stackrel{\frown}{AC} = 71^{\circ}.
b) Find mUWm\stackrel{\frown}{UW} given that mV=26m\angle V = 26^{\circ} and mUTV=36m\angle UTV = 36^{\circ}.
c) Find mPm\angle P given that mKL=52m\stackrel{\frown}{KL} = 52^{\circ} and mJN=18m\stackrel{\frown}{JN} = 18^{\circ}.

2. Solution Steps

a) To find the measure of the angle formed by two chords intersecting inside a circle, we use the formula:
m1=12(mDB+mAC)m\angle 1 = \frac{1}{2} (m\stackrel{\frown}{DB} + m\stackrel{\frown}{AC})
m1=12(82+71)m\angle 1 = \frac{1}{2} (82^{\circ} + 71^{\circ})
m1=12(153)m\angle 1 = \frac{1}{2} (153^{\circ})
m1=76.5m\angle 1 = 76.5^{\circ}
b) We are given mV=26m\angle V = 26^{\circ} and mUTV=36m\angle UTV = 36^{\circ}.
The angle UTVUTV is a central angle, so mUV=mUTV=36m\stackrel{\frown}{UV} = m\angle UTV = 36^{\circ}.
Since the entire circle is 360360^{\circ}, we have mVU+mUW+mWV=360m\stackrel{\frown}{VU} + m\stackrel{\frown}{UW} + m\stackrel{\frown}{WV} = 360^{\circ}.
Also, since V=26\angle V = 26^{\circ} is an inscribed angle subtending the arc UW\stackrel{\frown}{UW}, we have mUW=2×mV=2×26=52m\stackrel{\frown}{UW} = 2 \times m\angle V = 2 \times 26^{\circ} = 52^{\circ}.
Therefore, mUW=52m\stackrel{\frown}{UW} = 52^{\circ}.
c) To find the measure of an angle formed by two secants intersecting outside a circle, we use the formula:
mP=12(mKLmJN)m\angle P = \frac{1}{2} (m\stackrel{\frown}{KL} - m\stackrel{\frown}{JN})
mP=12(5218)m\angle P = \frac{1}{2} (52^{\circ} - 18^{\circ})
mP=12(34)m\angle P = \frac{1}{2} (34^{\circ})
mP=17m\angle P = 17^{\circ}

3. Final Answer

a) m1=76.5m\angle 1 = 76.5^{\circ}
b) mUW=52m\stackrel{\frown}{UW} = 52^{\circ}
c) mP=17m\angle P = 17^{\circ}

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