The problem requires filling in the blanks to factor linear expressions. We need to find the missing terms in the following expressions: $5x + 30 = 5(x + \_\_)$ $4cd + 18c = \_\_c(2d + 9)$ $12 + 20w = 4(\_\_ + 5w)$

AlgebraFactoringLinear ExpressionsAlgebraic Manipulation
2025/5/14

1. Problem Description

The problem requires filling in the blanks to factor linear expressions. We need to find the missing terms in the following expressions:
5x+30=5(x+__)5x + 30 = 5(x + \_\_)
4cd+18c=__c(2d+9)4cd + 18c = \_\_c(2d + 9)
12+20w=4(__+5w)12 + 20w = 4(\_\_ + 5w)

2. Solution Steps

For the first expression, 5x+30=5(x+__)5x + 30 = 5(x + \_\_), we can factor out a 5 from both terms:
5x+30=5(x+6)5x + 30 = 5(x + 6) since 56=305*6 = 30. So the missing term is
6.
For the second expression, 4cd+18c=__c(2d+9)4cd + 18c = \_\_c(2d + 9), we can factor out cc from both terms:
4cd+18c=c(4d+18)4cd + 18c = c(4d + 18). Now we have c(4d+18)=__c(2d+9)c(4d + 18) = \_\_c(2d + 9).
We notice that 2(2d+9)=4d+182*(2d + 9) = 4d + 18, so we can deduce that the missing term is

2. Thus, $4cd + 18c = 2c(2d + 9)$.

For the third expression, 12+20w=4(__+5w)12 + 20w = 4(\_\_ + 5w), we can factor out a 4 from both terms:
12+20w=4(3+5w)12 + 20w = 4(3 + 5w) since 43=124*3 = 12 and 45w=20w4*5w = 20w. So the missing term is
3.

3. Final Answer

5x+30=5(x+6)5x + 30 = 5(x + 6)
4cd+18c=2c(2d+9)4cd + 18c = 2c(2d + 9)
12+20w=4(3+5w)12 + 20w = 4(3 + 5w)

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