The problem asks to calculate the gradient of the line joining two given points in two separate cases. a) $(3, 0)$ and $(7, 1)$ b) $(-9, 6)$ and $(0, 3)$

GeometryCoordinate GeometryGradientSlopeLinear Equations
2025/5/14

1. Problem Description

The problem asks to calculate the gradient of the line joining two given points in two separate cases.
a) (3,0)(3, 0) and (7,1)(7, 1)
b) (9,6)(-9, 6) and (0,3)(0, 3)

2. Solution Steps

The gradient (mm) of a line joining two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
a) Given points are (3,0)(3, 0) and (7,1)(7, 1).
Let (x1,y1)=(3,0)(x_1, y_1) = (3, 0) and (x2,y2)=(7,1)(x_2, y_2) = (7, 1).
Using the gradient formula:
m=1073=14m = \frac{1 - 0}{7 - 3} = \frac{1}{4}
b) Given points are (9,6)(-9, 6) and (0,3)(0, 3).
Let (x1,y1)=(9,6)(x_1, y_1) = (-9, 6) and (x2,y2)=(0,3)(x_2, y_2) = (0, 3).
Using the gradient formula:
m=360(9)=39=13m = \frac{3 - 6}{0 - (-9)} = \frac{-3}{9} = -\frac{1}{3}

3. Final Answer

a) The gradient of the line joining (3,0)(3, 0) and (7,1)(7, 1) is 14\frac{1}{4}.
b) The gradient of the line joining (9,6)(-9, 6) and (0,3)(0, 3) is 13-\frac{1}{3}.

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