We are given that triangle $XYZ$ maps to triangle $MNO$ under the transformation $(x, y) \rightarrow (12x, 12y)$. We are given that $XY = 6$ and we need to find the length of $MN$.

GeometryGeometryTransformationsDilationSimilar Triangles
2025/5/15

1. Problem Description

We are given that triangle XYZXYZ maps to triangle MNOMNO under the transformation (x,y)(12x,12y)(x, y) \rightarrow (12x, 12y). We are given that XY=6XY = 6 and we need to find the length of MNMN.

2. Solution Steps

The transformation (x,y)(12x,12y)(x, y) \rightarrow (12x, 12y) is a dilation by a factor of
1

2. This means that the length of each side of the new triangle $MNO$ is 12 times the length of the corresponding side of triangle $XYZ$.

Since XYXY corresponds to MNMN, we have MN=12×XYMN = 12 \times XY.
Since XY=6XY = 6, we have MN=12×6=72MN = 12 \times 6 = 72.

3. Final Answer

MN=72MN = 72

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