The problem asks to solve the equation $16x + \frac{4}{3}y = 15$ for $y$ in terms of $x$.

AlgebraLinear EquationsSolving EquationsVariable Isolation
2025/5/18

1. Problem Description

The problem asks to solve the equation 16x+43y=1516x + \frac{4}{3}y = 15 for yy in terms of xx.

2. Solution Steps

First, isolate the term with yy by subtracting 16x16x from both sides of the equation:
43y=1516x\frac{4}{3}y = 15 - 16x
Next, multiply both sides of the equation by 34\frac{3}{4} to solve for yy:
y=34(1516x)y = \frac{3}{4}(15 - 16x)
Distribute the 34\frac{3}{4} to both terms inside the parenthesis:
y=34(15)34(16x)y = \frac{3}{4}(15) - \frac{3}{4}(16x)
y=454484xy = \frac{45}{4} - \frac{48}{4}x
y=45412xy = \frac{45}{4} - 12x

3. Final Answer

y=45412xy = \frac{45}{4} - 12x

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