The problem asks us to find the slope $m$ and $y$-intercept $b$ of the line given by the equation $4x + 5y = 20$. The correct answers have already been provided as $m = -\frac{4}{5}$ and $b = 4$.

1. Problem Description

The problem asks us to find the slope $m$ and $y$-intercept $b$ of the line given by the equation $4x + 5y = 20$. The correct answers have already been provided as $m = -\frac{4}{5}$ and $b = 4$.

2. Solution Steps

To find the slope and $y$-intercept of the line $4x + 5y = 20$, we can rewrite the equation in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept.

Subtract $4x$ from both sides of the equation:

$5y = -4x + 20$

Divide both sides by 5:

$y = -\frac{4}{5}x + \frac{20}{5}$

$y = -\frac{4}{5}x + 4$

Now, we can identify the slope and $y$-intercept.

The slope is $m = -\frac{4}{5}$.

The $y$-intercept is $b = 4$.

3. Final Answer

$m = -\frac{4}{5}$

$b = 4$