The problem asks to evaluate $(-8)^{\frac{2}{3}}$.AlgebraExponentsRadicalsSimplification2025/5/191. Problem DescriptionThe problem asks to evaluate (−8)23(-8)^{\frac{2}{3}}(−8)32.2. Solution StepsWe need to evaluate the expression (−8)23(-8)^{\frac{2}{3}}(−8)32. We can rewrite this expression as:(−8)23=((−8)13)2(-8)^{\frac{2}{3}} = ((-8)^{\frac{1}{3}})^2(−8)32=((−8)31)2First, we find the cube root of -8:(−8)13=−83=−2(-8)^{\frac{1}{3}} = \sqrt[3]{-8} = -2(−8)31=3−8=−2Then, we square the result:(−2)2=(−2)×(−2)=4(-2)^2 = (-2) \times (-2) = 4(−2)2=(−2)×(−2)=4Therefore, (−8)23=4(-8)^{\frac{2}{3}} = 4(−8)32=4.3. Final Answer4