The problem is to factor the given expression $9m^5n^2 + 12m^3n$.

AlgebraFactoringGreatest Common FactorPolynomials
2025/6/9

1. Problem Description

The problem is to factor the given expression 9m5n2+12m3n9m^5n^2 + 12m^3n.

2. Solution Steps

To factor the expression 9m5n2+12m3n9m^5n^2 + 12m^3n, we need to find the greatest common factor (GCF) of the two terms.
First, find the GCF of the coefficients 9 and
1

2. The factors of 9 are 1, 3, and

9. The factors of 12 are 1, 2, 3, 4, 6, and

1

2. The GCF of 9 and 12 is

3.
Next, find the GCF of the variable parts.
The first term has m5m^5 and the second term has m3m^3. The GCF of m5m^5 and m3m^3 is m3m^3.
The first term has n2n^2 and the second term has nn. The GCF of n2n^2 and nn is nn.
Therefore, the GCF of the two terms is 3m3n3m^3n.
Now, divide each term by the GCF:
9m5n23m3n=3m53n21=3m2n\frac{9m^5n^2}{3m^3n} = 3m^{5-3}n^{2-1} = 3m^2n
12m3n3m3n=4\frac{12m^3n}{3m^3n} = 4
So, we can write the expression as:
9m5n2+12m3n=3m3n(3m2n+4)9m^5n^2 + 12m^3n = 3m^3n(3m^2n + 4).

3. Final Answer

The factored expression is 3m3n(3m2n+4)3m^3n(3m^2n + 4).