The problem asks us to evaluate the expression $3pq^3r^3$ when $p=\frac{2}{3}$, $q=-2$, and $r=-1$.

AlgebraAlgebraic ExpressionsSubstitutionExponentsEvaluation
2025/6/9

1. Problem Description

The problem asks us to evaluate the expression 3pq3r33pq^3r^3 when p=23p=\frac{2}{3}, q=2q=-2, and r=1r=-1.

2. Solution Steps

First, substitute the given values into the expression:
3pq3r3=3(23)(2)3(1)33pq^3r^3 = 3 \cdot (\frac{2}{3}) \cdot (-2)^3 \cdot (-1)^3
Next, evaluate the powers:
(2)3=222=8(-2)^3 = -2 \cdot -2 \cdot -2 = -8
(1)3=111=1(-1)^3 = -1 \cdot -1 \cdot -1 = -1
Now, substitute these values back into the expression:
3(23)(8)(1)3 \cdot (\frac{2}{3}) \cdot (-8) \cdot (-1)
Multiply the terms:
3(23)=23 \cdot (\frac{2}{3}) = 2
(8)(1)=8(-8) \cdot (-1) = 8
So the expression becomes:
282 \cdot 8
Finally, multiply:
28=162 \cdot 8 = 16

3. Final Answer

The final answer is 16.

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