The problem asks which of the given options does NOT have an equal chance of occurring. A) Choose a number at random from 1 to 7 B) Toss a coin C) Choose a letter at random from the word SCHOOL

1. Problem Description

The problem asks which of the given options does NOT have an equal chance of occurring.

A) Choose a number at random from 1 to 7

B) Toss a coin

C) Choose a letter at random from the word SCHOOL

2. Solution Steps

Let's analyze each option:

A) Choose a number at random from 1 to

7. The numbers are 1, 2, 3, 4, 5, 6,

7. There are 7 numbers in total. If the choice is truly random, each number has a probability of $\frac{1}{7}$ of being chosen. Therefore, each number has an equal chance.

B) Toss a coin.

A coin has two sides: heads and tails. If the coin is fair, the probability of getting heads is $\frac{1}{2}$ and the probability of getting tails is $\frac{1}{2}$. Therefore, each side has an equal chance.

C) Choose a letter at random from the word SCHOOL.

The word SCHOOL has 6 letters: S, C, H, O, O, L.

The probability of choosing S is $\frac{1}{6}$.

The probability of choosing C is $\frac{1}{6}$.

The probability of choosing H is $\frac{1}{6}$.

The probability of choosing O is $\frac{2}{6} = \frac{1}{3}$.

The probability of choosing L is $\frac{1}{6}$.

Since the probability of choosing the letter O is $\frac{1}{3}$, which is different from the probability of choosing the other letters (which is $\frac{1}{6}$), the letters do NOT have an equal chance of being chosen.

Therefore, the answer is C.

3. Final Answer

C