A standard six-sided die is rolled. We need to find the probability that the number rolled is higher than 3.

1. Problem Description

A standard six-sided die is rolled. We need to find the probability that the number rolled is higher than

3.

2. Solution Steps

A standard die has 6 faces, numbered 1, 2, 3, 4, 5, and

6. The numbers higher than 3 are 4, 5, and

6. There are 3 such numbers.

The total number of possible outcomes is

6. The number of favorable outcomes (numbers higher than 3) is

3. The probability of an event is calculated as:

$Probability = \frac{Number \ of \ favorable \ outcomes}{Total \ number \ of \ possible \ outcomes}$

In this case:

$Probability = \frac{3}{6}$

Simplify the fraction:

$Probability = \frac{1}{2}$

3. Final Answer

The probability that the cube shows a number higher than 3 is $\frac{1}{2}$.