The problem asks to solve the equation $3v = h^2(3r - h)$ for $r$, where $v$ and $h$ are real numbers.

AlgebraEquation SolvingVariable IsolationAlgebraic Manipulation
2025/5/25

1. Problem Description

The problem asks to solve the equation 3v=h2(3rh)3v = h^2(3r - h) for rr, where vv and hh are real numbers.

2. Solution Steps

We want to isolate rr in the equation 3v=h2(3rh)3v = h^2(3r - h).
First, distribute h2h^2 on the right side of the equation:
3v=3h2rh33v = 3h^2r - h^3
Next, add h3h^3 to both sides of the equation:
3v+h3=3h2r3v + h^3 = 3h^2r
Finally, divide both sides by 3h23h^2 to solve for rr:
r=3v+h33h2r = \frac{3v + h^3}{3h^2}
We can also write this as:
r=3v3h2+h33h2r = \frac{3v}{3h^2} + \frac{h^3}{3h^2}
r=vh2+h3r = \frac{v}{h^2} + \frac{h}{3}

3. Final Answer

r=3v+h33h2r = \frac{3v + h^3}{3h^2} or r=vh2+h3r = \frac{v}{h^2} + \frac{h}{3}

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