The problem describes a triangular warning sign with an area of 340 square inches. We are given that the base is 14 inches longer than the altitude (height). We are also given that the altitude is 20 inches. We need to find the length of the base.

1. Problem Description

The problem describes a triangular warning sign with an area of 340 square inches. We are given that the base is 14 inches longer than the altitude (height). We are also given that the altitude is 20 inches. We need to find the length of the base.

2. Solution Steps

Let $A$ be the area of the triangle, $b$ be the base, and $h$ be the altitude (height).

The area of a triangle is given by the formula:

$A = \frac{1}{2}bh$

We are given that $A = 340$ square inches.

We are given that the altitude, $h = 20$ inches.

We are also given that the base, $b$, is 14 inches longer than the altitude, so $b = h + 14$.

Substituting the value of $h$, we get $b = 20 + 14 = 34$ inches.

3. Final Answer

The base is 34 inches.