The problem asks us to factor the expression $12a^3b - 27ab^3$.

AlgebraFactoringPolynomialsGreatest Common FactorDifference of Squares
2025/3/25

1. Problem Description

The problem asks us to factor the expression 12a3b27ab312a^3b - 27ab^3.

2. Solution Steps

First, we find the greatest common factor (GCF) of the two terms 12a3b12a^3b and 27ab327ab^3.
The GCF of 12 and 27 is

3. The GCF of $a^3$ and $a$ is $a$. The GCF of $b$ and $b^3$ is $b$.

Therefore, the GCF of the two terms is 3ab3ab.
We can factor out 3ab3ab from the expression:
12a3b27ab3=3ab(4a29b2)12a^3b - 27ab^3 = 3ab(4a^2 - 9b^2)
Now we notice that 4a29b24a^2 - 9b^2 is a difference of squares: 4a2=(2a)24a^2 = (2a)^2 and 9b2=(3b)29b^2 = (3b)^2.
We can use the difference of squares formula:
x2y2=(xy)(x+y)x^2 - y^2 = (x - y)(x + y)
In this case, x=2ax = 2a and y=3by = 3b.
So, 4a29b2=(2a3b)(2a+3b)4a^2 - 9b^2 = (2a - 3b)(2a + 3b).
Thus, the fully factored expression is:
12a3b27ab3=3ab(2a3b)(2a+3b)12a^3b - 27ab^3 = 3ab(2a - 3b)(2a + 3b)

3. Final Answer

3ab(2a3b)(2a+3b)3ab(2a - 3b)(2a + 3b)

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