The problem has three parts: (a) Factorize the expression $5ay - by + 15a - 3b$. (b) Solve the equation $\frac{6}{4p-1} = \frac{4}{3(p+4)}$. (c) Esi and Kofi shared GH¢21,000.00 in the ratio 2:5. Determine how much more Kofi received than Esi.

AlgebraFactorizationLinear EquationsRatio and Proportion
2025/5/30

1. Problem Description

The problem has three parts:
(a) Factorize the expression 5ayby+15a3b5ay - by + 15a - 3b.
(b) Solve the equation 64p1=43(p+4)\frac{6}{4p-1} = \frac{4}{3(p+4)}.
(c) Esi and Kofi shared GH¢21,000.00 in the ratio 2:

5. Determine how much more Kofi received than Esi.

2. Solution Steps

(a) Factorization:
We want to factorize 5ayby+15a3b5ay - by + 15a - 3b.
We can group the terms as follows: (5ayby)+(15a3b)(5ay - by) + (15a - 3b).
Now factor out common terms from each group: y(5ab)+3(5ab)y(5a - b) + 3(5a - b).
Since both terms have (5ab)(5a - b) as a factor, we can factor it out: (5ab)(y+3)(5a - b)(y + 3).
(b) Solving the equation:
We have 64p1=43(p+4)\frac{6}{4p-1} = \frac{4}{3(p+4)}.
Cross-multiply to get 63(p+4)=4(4p1)6 \cdot 3(p+4) = 4(4p-1).
18(p+4)=16p418(p+4) = 16p - 4
18p+72=16p418p + 72 = 16p - 4
18p16p=47218p - 16p = -4 - 72
2p=762p = -76
p=762p = \frac{-76}{2}
p=38p = -38
(c) Ratio problem:
Total amount = GH¢21,000.00
Ratio of Esi to Kofi = 2:5
Total ratio = 2 + 5 = 7
Esi's share =27×21000=2×3000=6000= \frac{2}{7} \times 21000 = 2 \times 3000 = 6000
Kofi's share =57×21000=5×3000=15000= \frac{5}{7} \times 21000 = 5 \times 3000 = 15000
Difference = Kofi's share - Esi's share = 15000 - 6000 = 9000

3. Final Answer

(a) (5ab)(y+3)(5a - b)(y + 3)
(b) p=38p = -38
(c) GH¢9,000.00

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