We are asked to find the value of $P = \tan 43^{\circ} \tan 44^{\circ} \tan 45^{\circ} \tan 46^{\circ} \tan 47^{\circ}$.

1. Problem Description

We are asked to find the value of $P = \tan 43^{\circ} \tan 44^{\circ} \tan 45^{\circ} \tan 46^{\circ} \tan 47^{\circ}$.

2. Solution Steps

We can use the fact that $\tan(90^{\circ} - x) = \cot x = \frac{1}{\tan x}$.

Also, we know that $\tan 45^{\circ} = 1$.

We can rewrite the expression as:

$P = \tan 43^{\circ} \tan 44^{\circ} \tan 45^{\circ} \tan 46^{\circ} \tan 47^{\circ}$

$P = \tan 43^{\circ} \tan 44^{\circ} (1) \tan (90^{\circ} - 44^{\circ}) \tan (90^{\circ} - 43^{\circ})$

$P = \tan 43^{\circ} \tan 44^{\circ} \tan (90^{\circ} - 44^{\circ}) \tan (90^{\circ} - 43^{\circ})$

Since $\tan (90^{\circ} - x) = \cot x$, we have

$P = \tan 43^{\circ} \tan 44^{\circ} \cot 44^{\circ} \cot 43^{\circ}$

Since $\cot x = \frac{1}{\tan x}$, we have

$P = \tan 43^{\circ} \tan 44^{\circ} \frac{1}{\tan 44^{\circ}} \frac{1}{\tan 43^{\circ}}$

$P = \frac{\tan 43^{\circ}}{\tan 43^{\circ}} \frac{\tan 44^{\circ}}{\tan 44^{\circ}}$

$P = 1 \cdot 1 = 1$

3. Final Answer

The final answer is 1.