We are asked to find the factors of the quadratic function $f(x) = x^2 + 3x + 2$.

AlgebraQuadratic EquationsFactorizationRoots of Equations
2025/3/26

1. Problem Description

We are asked to find the factors of the quadratic function f(x)=x2+3x+2f(x) = x^2 + 3x + 2.

2. Solution Steps

We can factor the quadratic expression x2+3x+2x^2 + 3x + 2. We are looking for two numbers that multiply to 2 and add up to

3. These numbers are 1 and

2. Therefore, we can write the expression as:

x2+3x+2=(x+1)(x+2)x^2 + 3x + 2 = (x+1)(x+2)
To find the roots (or zeros) of the function, we set f(x)=0f(x) = 0:
(x+1)(x+2)=0(x+1)(x+2) = 0
This implies that x+1=0x+1 = 0 or x+2=0x+2 = 0.
Solving for xx, we get x=1x = -1 or x=2x = -2.
The factors are 1-1 and 2-2.

3. Final Answer

-1, -2

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