The problem asks us to find the size of angle $DAB$ in a quadrilateral $ABCD$. We are given that angle $ADC = 97^\circ$, angle $ABC = 64^\circ$, and angle $DCB = 90^\circ$ (indicated by the right angle symbol).

GeometryQuadrilateralsAnglesGeometric Proof
2025/6/3

1. Problem Description

The problem asks us to find the size of angle DABDAB in a quadrilateral ABCDABCD. We are given that angle ADC=97ADC = 97^\circ, angle ABC=64ABC = 64^\circ, and angle DCB=90DCB = 90^\circ (indicated by the right angle symbol).

2. Solution Steps

The sum of the interior angles in a quadrilateral is 360360^\circ. Therefore, we have
ADC+DCB+CBA+BAD=360ADC + DCB + CBA + BAD = 360^\circ.
We are given the following angles:
ADC=97ADC = 97^\circ
DCB=90DCB = 90^\circ
CBA=64CBA = 64^\circ
We want to find the size of angle DABDAB, which is BADBAD. Substituting the known values into the equation:
97+90+64+BAD=36097^\circ + 90^\circ + 64^\circ + BAD = 360^\circ
251+BAD=360251^\circ + BAD = 360^\circ
BAD=360251BAD = 360^\circ - 251^\circ
BAD=109BAD = 109^\circ

3. Final Answer

The size of angle DABDAB is 109109^\circ.

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