The problem provides the measures of the six interior angles of a hexagon in terms of $x$. The task is to find the value of $x$. The given angles are $107^\circ$, $(2x)^\circ$, $150^\circ$, $95^\circ$, $(2x-15)^\circ$, and $123^\circ$.

GeometryPolygonHexagonInterior AnglesAngle SumAlgebra
2025/6/3

1. Problem Description

The problem provides the measures of the six interior angles of a hexagon in terms of xx. The task is to find the value of xx. The given angles are 107107^\circ, (2x)(2x)^\circ, 150150^\circ, 9595^\circ, (2x15)(2x-15)^\circ, and 123123^\circ.

2. Solution Steps

The sum of the interior angles of a polygon with nn sides is given by the formula:
S=(n2)×180S = (n-2) \times 180^\circ
For a hexagon, n=6n=6, so the sum of the interior angles is:
S=(62)×180=4×180=720S = (6-2) \times 180^\circ = 4 \times 180^\circ = 720^\circ
Now, we can write an equation by summing the given angles and setting it equal to 720720^\circ:
107+2x+150+95+(2x15)+123=720107 + 2x + 150 + 95 + (2x-15) + 123 = 720
Combine the constant terms:
107+150+9515+123=460107 + 150 + 95 - 15 + 123 = 460
So, the equation becomes:
460+2x+2x=720460 + 2x + 2x = 720
460+4x=720460 + 4x = 720
Subtract 460 from both sides:
4x=7204604x = 720 - 460
4x=2604x = 260
Divide by 4:
x=2604x = \frac{260}{4}
x=65x = 65

3. Final Answer

The value of xx is
6

5. So, the answer is B. 65.

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