The problem asks us to compute the first five terms of the sequence {$c_n$} defined by the formula $c_n = 4n - 2$ for all positive integers $n$.

1. Problem Description

The problem asks us to compute the first five terms of the sequence {$c_n$} defined by the formula $c_n = 4n - 2$ for all positive integers $n$.

2. Solution Steps

We need to find $c_1, c_2, c_3, c_4,$ and $c_5$. We do this by substituting $n = 1, 2, 3, 4, 5$ into the formula $c_n = 4n - 2$.

For $n=1$:

$c_1 = 4(1) - 2 = 4 - 2 = 2$

For $n=2$:

$c_2 = 4(2) - 2 = 8 - 2 = 6$

For $n=3$:

$c_3 = 4(3) - 2 = 12 - 2 = 10$

For $n=4$:

$c_4 = 4(4) - 2 = 16 - 2 = 14$

For $n=5$:

$c_5 = 4(5) - 2 = 20 - 2 = 18$

3. Final Answer

The first five terms of the sequence are 2, 6, 10, 14, 18.