The image presents a set of quadratic equations that need to be solved by factoring. I will solve problems 4, 5, 6, 7, and 8. Problem 3 is already solved.

AlgebraQuadratic EquationsFactorizationSolving Equations
2025/6/4

1. Problem Description

The image presents a set of quadratic equations that need to be solved by factoring. I will solve problems 4, 5, 6, 7, and

8. Problem 3 is already solved.

2. Solution Steps

Problem 4: 7x2+42x49=07x^2 + 42x - 49 = 0
Step 1: Divide the entire equation by 7 to simplify it.
x2+6x7=0x^2 + 6x - 7 = 0
Step 2: Factor the quadratic expression.
(x+7)(x1)=0(x+7)(x-1) = 0
Step 3: Set each factor equal to zero and solve for xx.
x+7=0x+7 = 0 or x1=0x-1 = 0
x=7x = -7 or x=1x = 1
Problem 5: 8x236x+13=38x^2 - 36x + 13 = -3
Step 1: Add 3 to both sides of the equation to set it equal to zero.
8x236x+16=08x^2 - 36x + 16 = 0
Step 2: Divide the entire equation by 4 to simplify it.
2x29x+4=02x^2 - 9x + 4 = 0
Step 3: Factor the quadratic expression.
(2x1)(x4)=0(2x-1)(x-4) = 0
Step 4: Set each factor equal to zero and solve for xx.
2x1=02x-1 = 0 or x4=0x-4 = 0
2x=12x = 1 or x=4x = 4
x=12x = \frac{1}{2} or x=4x = 4
Problem 6: 6a23a48=36a^2 - 3a - 48 = -3
Step 1: Add 3 to both sides of the equation to set it equal to zero.
6a23a45=06a^2 - 3a - 45 = 0
Step 2: Divide the entire equation by 3 to simplify it.
2a2a15=02a^2 - a - 15 = 0
Step 3: Factor the quadratic expression.
(2a+5)(a3)=0(2a+5)(a-3) = 0
Step 4: Set each factor equal to zero and solve for aa.
2a+5=02a+5 = 0 or a3=0a-3 = 0
2a=52a = -5 or a=3a = 3
a=52a = -\frac{5}{2} or a=3a = 3
Problem 7: 42x2144x+62=842x^2 - 144x + 62 = 8
Step 1: Subtract 8 from both sides of the equation to set it equal to zero.
42x2144x+54=042x^2 - 144x + 54 = 0
Step 2: Divide the entire equation by 6 to simplify it.
7x224x+9=07x^2 - 24x + 9 = 0
Step 3: Factor the quadratic expression.
(7x3)(x3)=0(7x-3)(x-3) = 0
Step 4: Set each factor equal to zero and solve for xx.
7x3=07x-3 = 0 or x3=0x-3 = 0
7x=37x = 3 or x=3x = 3
x=37x = \frac{3}{7} or x=3x = 3
Problem 8: 10n210n=5n10n^2 - 10n = -5n
Step 1: Add 5n5n to both sides of the equation to set it equal to zero.
10n25n=010n^2 - 5n = 0
Step 2: Factor out the common term 5n5n.
5n(2n1)=05n(2n-1) = 0
Step 3: Set each factor equal to zero and solve for nn.
5n=05n = 0 or 2n1=02n-1 = 0
n=0n = 0 or 2n=12n = 1
n=0n = 0 or n=12n = \frac{1}{2}

3. Final Answer

Problem 4: x=7x = -7 or x=1x = 1
Problem 5: x=12x = \frac{1}{2} or x=4x = 4
Problem 6: a=52a = -\frac{5}{2} or a=3a = 3
Problem 7: x=37x = \frac{3}{7} or x=3x = 3
Problem 8: n=0n = 0 or n=12n = \frac{1}{2}

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