The problem states "Доказать особину средње линије троугла" which translates to "Prove the property of the midline of a triangle". The midline of a triangle is the line segment connecting the midpoints of two sides of the triangle. The task is to prove properties about the midline, specifically that the midline is parallel to the third side and half its length.

GeometryTriangleMidlineParallel LinesSimilaritySAS Similarity
2025/3/27

1. Problem Description

The problem states "Доказать особину средње линије троугла" which translates to "Prove the property of the midline of a triangle". The midline of a triangle is the line segment connecting the midpoints of two sides of the triangle. The task is to prove properties about the midline, specifically that the midline is parallel to the third side and half its length.

2. Solution Steps

Let's denote the triangle as ABCABC.
Let DD be the midpoint of side ABAB and EE be the midpoint of side ACAC.
Then, DEDE is the midline of triangle ABCABC.
We want to prove that DEDE is parallel to BCBC and DE=12BCDE = \frac{1}{2}BC.
Consider triangle ADEADE and triangle ABCABC.
Since DD is the midpoint of ABAB, we have AD=12ABAD = \frac{1}{2}AB.
Since EE is the midpoint of ACAC, we have AE=12ACAE = \frac{1}{2}AC.
Thus, ADAB=AEAC=12\frac{AD}{AB} = \frac{AE}{AC} = \frac{1}{2}.
Also, angle AA is common to both triangles ADEADE and ABCABC.
Therefore, by the Side-Angle-Side (SAS) similarity criterion, triangle ADEADE is similar to triangle ABCABC.
Since triangle ADEADE is similar to triangle ABCABC, their corresponding angles are equal.
That is, angle ADEADE = angle ABCABC and angle AEDAED = angle ACBACB.
Since these are corresponding angles, it implies that DEDE is parallel to BCBC.
Also, since the triangles are similar, the ratio of their corresponding sides is constant.
Therefore, DEBC=ADAB=AEAC=12\frac{DE}{BC} = \frac{AD}{AB} = \frac{AE}{AC} = \frac{1}{2}.
This implies DE=12BCDE = \frac{1}{2}BC.
Thus, we have proven that the midline DEDE is parallel to the third side BCBC and its length is half the length of the third side.

3. Final Answer

The midline of a triangle is parallel to the third side and its length is half the length of the third side.

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