The problem asks to find the size of angle $a$ in the given quadrilateral. The other angles in the quadrilateral are $123^{\circ}$, $101^{\circ}$, and $85^{\circ}$.

GeometryQuadrilateralsAnglesPolygon Interior Angles
2025/6/8

1. Problem Description

The problem asks to find the size of angle aa in the given quadrilateral. The other angles in the quadrilateral are 123123^{\circ}, 101101^{\circ}, and 8585^{\circ}.

2. Solution Steps

The sum of the interior angles of a quadrilateral is 360360^{\circ}.
The formula for the sum of interior angles of a polygon with nn sides is:
(n2)×180(n-2) \times 180^{\circ}.
For a quadrilateral, n=4n=4, so the sum of the interior angles is
(42)×180=2×180=360(4-2) \times 180^{\circ} = 2 \times 180^{\circ} = 360^{\circ}.
Therefore, we have:
123+101+85+a=360123^{\circ} + 101^{\circ} + 85^{\circ} + a = 360^{\circ}
309+a=360309^{\circ} + a = 360^{\circ}
a=360309a = 360^{\circ} - 309^{\circ}
a=51a = 51^{\circ}

3. Final Answer

The size of angle aa is 5151^{\circ}.

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