We are given a cyclic quadrilateral QRST inscribed in a circle. We are given that $\angle Q = 95^\circ$, $\angle T = 80^\circ$, $\angle R = x^\circ$, and $\angle S = y^\circ$. We need to find the values of $x$ and $y$.

GeometryCyclic QuadrilateralAnglesSupplementary AnglesCircle Geometry
2025/3/28

1. Problem Description

We are given a cyclic quadrilateral QRST inscribed in a circle. We are given that Q=95\angle Q = 95^\circ, T=80\angle T = 80^\circ, R=x\angle R = x^\circ, and S=y\angle S = y^\circ. We need to find the values of xx and yy.

2. Solution Steps

Since QRST is a cyclic quadrilateral, opposite angles are supplementary, meaning their sum is 180180^\circ. Therefore, we have:
Q+S=180\angle Q + \angle S = 180^\circ
R+T=180\angle R + \angle T = 180^\circ
We are given Q=95\angle Q = 95^\circ and T=80\angle T = 80^\circ. We can substitute these values into the equations above.
95+y=18095^\circ + y^\circ = 180^\circ
x+80=180x^\circ + 80^\circ = 180^\circ
Now we can solve for xx and yy.
y=18095=85y = 180 - 95 = 85
x=18080=100x = 180 - 80 = 100
Therefore, x=100x = 100 and y=85y = 85.

3. Final Answer

x = 100
y = 85

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