We are given a system of two linear equations: $y = -3x + 2$ $y = x - 2$ We need to find the solution to this system, which is the point $(x, y)$ that satisfies both equations.

AlgebraLinear EquationsSystems of EquationsSubstitution MethodCoordinate Geometry
2025/3/28

1. Problem Description

We are given a system of two linear equations:
y=3x+2y = -3x + 2
y=x2y = x - 2
We need to find the solution to this system, which is the point (x,y)(x, y) that satisfies both equations.

2. Solution Steps

We can use the substitution method to solve this system of equations. Since both equations are already solved for yy, we can set them equal to each other:
3x+2=x2-3x + 2 = x - 2
Now, we solve for xx:
3xx=22-3x - x = -2 - 2
4x=4-4x = -4
x=44x = \frac{-4}{-4}
x=1x = 1
Now that we have found the value of xx, we can substitute it into either of the original equations to find the value of yy. Let's use the second equation:
y=x2y = x - 2
y=12y = 1 - 2
y=1y = -1
Therefore, the solution to the system of equations is (1,1)(1, -1).

3. Final Answer

The solution to the system of equations is (1,1)(1, -1).

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