The problem is to solve the linear equation $\frac{b}{3} + 15 = -8$ for the variable $b$.

AlgebraLinear EquationsSolving Equations
2025/3/9

1. Problem Description

The problem is to solve the linear equation b3+15=8\frac{b}{3} + 15 = -8 for the variable bb.

2. Solution Steps

To solve the equation b3+15=8\frac{b}{3} + 15 = -8, we first subtract 15 from both sides of the equation:
b3+1515=815\frac{b}{3} + 15 - 15 = -8 - 15
b3=23\frac{b}{3} = -23
Now, we multiply both sides of the equation by 3:
3b3=3(23)3 \cdot \frac{b}{3} = 3 \cdot (-23)
b=69b = -69

3. Final Answer

b=69b = -69

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