The problem asks to find the size of angle $DAB$ in the quadrilateral $ABCD$. We are given the angles at vertices $D$, $C$, and $B$. Angle $ADC$ is $96^\circ$, angle $BCD$ is $90^\circ$ (indicated by the square symbol), and angle $ABC$ is $67^\circ$.

1. Problem Description

The problem asks to find the size of angle $DAB$ in the quadrilateral $ABCD$. We are given the angles at vertices $D$, $C$, and $B$. Angle $ADC$ is $96^\circ$, angle $BCD$ is $90^\circ$ (indicated by the square symbol), and angle $ABC$ is $67^\circ$.

2. Solution Steps

To find the size of angle $DAB$, we use the fact that the sum of the interior angles of a quadrilateral is $360^\circ$. Let $x$ be the measure of angle $DAB$. Then,

$x + 96^\circ + 90^\circ + 67^\circ = 360^\circ$.

Combining the known angles, we have:

$96^\circ + 90^\circ + 67^\circ = 253^\circ$.

So,

$x + 253^\circ = 360^\circ$.

Subtracting $253^\circ$ from both sides, we get:

$x = 360^\circ - 253^\circ$.

$x = 107^\circ$.

3. Final Answer

The size of angle $DAB$ is $107^\circ$.