The problem asks us to find the size of angle $f$ in the given figure. The figure is a quadrilateral with one interior angle of $226^\circ$ and two exterior angles of $35^\circ$ and $42^\circ$ respectively.

GeometryQuadrilateralExterior AnglesInterior AnglesAngle Calculation
2025/6/22

1. Problem Description

The problem asks us to find the size of angle ff in the given figure. The figure is a quadrilateral with one interior angle of 226226^\circ and two exterior angles of 3535^\circ and 4242^\circ respectively.

2. Solution Steps

First, we need to find the interior angles of the quadrilateral corresponding to the exterior angles of 3535^\circ and 4242^\circ.
The sum of an interior angle and its corresponding exterior angle is 180180^\circ.
So, the interior angle corresponding to the 3535^\circ exterior angle is 18035=145180^\circ - 35^\circ = 145^\circ.
The interior angle corresponding to the 4242^\circ exterior angle is 18042=138180^\circ - 42^\circ = 138^\circ.
The sum of the interior angles of a quadrilateral is 360360^\circ.
Let ff be the unknown angle. Then, we have:
f+145+138+226=360f + 145^\circ + 138^\circ + 226^\circ = 360^\circ
f+509=360f + 509^\circ = 360^\circ
However, this doesn't make sense because it would mean ff is negative. Instead, the figure is a concave quadrilateral. Consider the interior reflex angle to be 360226=134360^\circ - 226^\circ = 134^\circ.
Then, we have:
f+145+138+134=360f + 145^\circ + 138^\circ + 134^\circ = 360^\circ
f+417=360f + 417^\circ = 360^\circ. Again, this doesn't make sense.
The angle of 226226^\circ is an external angle. Hence, consider a triangle formed by extending the lines.
The internal angle at the bottom left is 3535^\circ, and the internal angle at the bottom right is 4242^\circ.
The angle adjacent to 226226^\circ is 360226=134360^\circ - 226^\circ = 134^\circ.
The sum of angles in a quadrilateral is 360360^\circ.
Thus, 35+42+x+f=36035^\circ + 42^\circ + x + f = 360^\circ, where x is the supplementary angle of
2
2

6. $x = 360 - 226 = 134$

So, f+35+42=226f + 35 + 42 = 226 because the exterior angle of the vertex is equal to sum of the angles at the remote interior vertices.
f+77=226f + 77 = 226
f=22677f = 226 - 77
f=149f = 149

3. Final Answer

The final answer is 149\boxed{149}

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