The problem states that a sequence is defined by the formula $a_n = p + qn$. We are given that the seventh term ($a_7$) is 19 and the fifteenth term ($a_{15}$) is 43. We need to find the values of $p$ and $q$.

AlgebraLinear EquationsSequencesArithmetic SequencesSystems of Equations
2025/6/24

1. Problem Description

The problem states that a sequence is defined by the formula an=p+qna_n = p + qn. We are given that the seventh term (a7a_7) is 19 and the fifteenth term (a15a_{15}) is
4

3. We need to find the values of $p$ and $q$.

2. Solution Steps

We are given the following information:
an=p+qna_n = p + qn
a7=19a_7 = 19
a15=43a_{15} = 43
Using the formula for ana_n, we can write equations for a7a_7 and a15a_{15}:
a7=p+7q=19a_7 = p + 7q = 19
a15=p+15q=43a_{15} = p + 15q = 43
We have a system of two linear equations with two variables, pp and qq:
p+7q=19p + 7q = 19
p+15q=43p + 15q = 43
We can solve this system of equations using substitution or elimination. Let's use elimination. Subtract the first equation from the second equation:
(p+15q)(p+7q)=4319(p + 15q) - (p + 7q) = 43 - 19
p+15qp7q=24p + 15q - p - 7q = 24
8q=248q = 24
q=248q = \frac{24}{8}
q=3q = 3
Now, substitute the value of qq into the first equation to find pp:
p+7q=19p + 7q = 19
p+7(3)=19p + 7(3) = 19
p+21=19p + 21 = 19
p=1921p = 19 - 21
p=2p = -2

3. Final Answer

p=2p = -2
q=3q = 3

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