The problem asks to factor the quadratic expression $2x^2 - x - 15$.

AlgebraQuadratic EquationsFactorizationAlgebraic Manipulation
2025/6/24

1. Problem Description

The problem asks to factor the quadratic expression 2x2x152x^2 - x - 15.

2. Solution Steps

We need to find two numbers whose product is equal to 2(15)=302 * (-15) = -30 and whose sum is equal to 1-1.
The numbers are 6-6 and 55, since (6)5=30(-6) * 5 = -30 and (6)+5=1(-6) + 5 = -1.
We rewrite the middle term x-x as 6x+5x-6x + 5x:
2x2x15=2x26x+5x152x^2 - x - 15 = 2x^2 - 6x + 5x - 15.
Now, we factor by grouping:
2x26x+5x15=2x(x3)+5(x3)2x^2 - 6x + 5x - 15 = 2x(x - 3) + 5(x - 3).
We can now factor out (x3)(x - 3) from both terms:
2x(x3)+5(x3)=(2x+5)(x3)2x(x - 3) + 5(x - 3) = (2x + 5)(x - 3).

3. Final Answer

(2x+5)(x3)(2x + 5)(x - 3)

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