The problem asks us to evaluate the function $f(x) = 2x^2 + x + 2$ at $x = -2$. In other words, we need to find the value of $f(-2)$.

AlgebraFunctionsPolynomialsEvaluation
2025/7/3

1. Problem Description

The problem asks us to evaluate the function f(x)=2x2+x+2f(x) = 2x^2 + x + 2 at x=2x = -2. In other words, we need to find the value of f(2)f(-2).

2. Solution Steps

To find f(2)f(-2), we substitute 2-2 for xx in the expression for f(x)f(x).
f(x)=2x2+x+2f(x) = 2x^2 + x + 2
f(2)=2(2)2+(2)+2f(-2) = 2(-2)^2 + (-2) + 2
First, we calculate (2)2(-2)^2:
(2)2=(2)×(2)=4(-2)^2 = (-2) \times (-2) = 4
Then we substitute this value back into the equation:
f(2)=2(4)2+2f(-2) = 2(4) - 2 + 2
Next, we multiply 2 by 4:
f(2)=82+2f(-2) = 8 - 2 + 2
Finally, we simplify:
f(2)=8f(-2) = 8

3. Final Answer

8

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