We are given a set of systems of linear equations. We need to solve each system for $x$ and $y$ using the substitution method. Let's solve the 4th system. System 4: $y = -3x$ $4x - 2y = -20$

1. Problem Description

We are given a set of systems of linear equations. We need to solve each system for $x$ and $y$ using the substitution method. Let's solve the 4th system.

System 4:

$y = -3x$

$4x - 2y = -20$

2. Solution Steps

We are given the system:

$y = -3x$

$4x - 2y = -20$

We can substitute the first equation into the second equation to solve for $x$:

$4x - 2(-3x) = -20$

$4x + 6x = -20$

$10x = -20$

$x = -2$

Now, we substitute $x = -2$ into the first equation to solve for $y$:

$y = -3(-2)$

$y = 6$

So the solution is $x = -2$ and $y = 6$.

3. Final Answer

$x = -2, y = 6$