We are given the equation $9^{z+5} = 3^z$ and we need to solve for $z$.

AlgebraExponentsEquationsSolving Equations
2025/6/5

1. Problem Description

We are given the equation 9z+5=3z9^{z+5} = 3^z and we need to solve for zz.

2. Solution Steps

We can rewrite 9 as 323^2. Substituting this into the given equation yields:
(32)z+5=3z(3^2)^{z+5} = 3^z
Using the power of a power rule (am)n=amn(a^m)^n = a^{mn}, we have
32(z+5)=3z3^{2(z+5)} = 3^z
Since the bases are equal, we can equate the exponents:
2(z+5)=z2(z+5) = z
Distribute the 2 on the left side:
2z+10=z2z + 10 = z
Subtract 2z2z from both sides:
10=z2z10 = z - 2z
10=z10 = -z
Multiply both sides by -1:
z=10z = -10

3. Final Answer

The final answer is z=10z = -10.

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