The problem is to evaluate the indefinite integral of $3x^{-4}$.

AnalysisIntegrationIndefinite IntegralPower RuleCalculus
2025/7/16

1. Problem Description

The problem is to evaluate the indefinite integral of 3x43x^{-4}.

2. Solution Steps

We need to find the integral of 3x43x^{-4} with respect to xx. We can use the power rule for integration, which states that xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C, where n1n \neq -1 and CC is the constant of integration.
In this case, we have:
3x4dx=3x4dx\int 3x^{-4} dx = 3 \int x^{-4} dx
Using the power rule, we get:
3x4dx=3x4+14+1+C=3x33+C=x3+C=1x3+C3 \int x^{-4} dx = 3 \cdot \frac{x^{-4+1}}{-4+1} + C = 3 \cdot \frac{x^{-3}}{-3} + C = -x^{-3} + C = -\frac{1}{x^3} + C

3. Final Answer

The indefinite integral of 3x43x^{-4} is 1x3+C-\frac{1}{x^3} + C. Therefore, the correct answer is C.
Final Answer: C

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