An employment agency pays heavy equipment operators $139 per day and general laborers $100 per day. If 39 people were hired and the total payroll was $4524, we need to find the number of heavy equipment operators and general laborers employed.

AlgebraSystems of EquationsWord ProblemLinear EquationsProblem Solving
2025/3/11

1. Problem Description

An employment agency pays heavy equipment operators 139perdayandgenerallaborers139 per day and general laborers 100 per day. If 39 people were hired and the total payroll was $4524, we need to find the number of heavy equipment operators and general laborers employed.

2. Solution Steps

Let xx be the number of heavy equipment operators and yy be the number of general laborers.
We are given two pieces of information:
The total number of people hired is
3

9. $x + y = 39$

The total payroll is $
4
5
2

4. $139x + 100y = 4524$

We have a system of two equations with two variables:
x+y=39x + y = 39
139x+100y=4524139x + 100y = 4524
We can solve for yy in the first equation:
y=39xy = 39 - x
Substitute this expression for yy into the second equation:
139x+100(39x)=4524139x + 100(39 - x) = 4524
139x+3900100x=4524139x + 3900 - 100x = 4524
39x=4524390039x = 4524 - 3900
39x=62439x = 624
x=62439x = \frac{624}{39}
x=16x = 16
Now we can find yy:
y=39x=3916=23y = 39 - x = 39 - 16 = 23
So, there are 16 heavy equipment operators and 23 general laborers.

3. Final Answer

The number of heavy equipment operators hired was
1

6. The number of general laborers hired was 23.

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