An employment agency pays heavy equipment operators $130 per day and general laborers $90 per day. A total of 37 people were hired, and the total payroll was $4210. We need to find out how many heavy equipment operators and how many general laborers were hired.

AlgebraSystems of EquationsWord ProblemLinear Equations
2025/3/11

1. Problem Description

An employment agency pays heavy equipment operators 130perdayandgenerallaborers130 per day and general laborers 90 per day. A total of 37 people were hired, and the total payroll was $
4
2
1

0. We need to find out how many heavy equipment operators and how many general laborers were hired.

2. Solution Steps

Let xx be the number of heavy equipment operators and yy be the number of general laborers.
We can set up a system of two equations with two variables:
x+y=37x + y = 37
130x+90y=4210130x + 90y = 4210
We can solve for yy in the first equation:
y=37xy = 37 - x
Substitute this expression for yy into the second equation:
130x+90(37x)=4210130x + 90(37 - x) = 4210
130x+333090x=4210130x + 3330 - 90x = 4210
40x=4210333040x = 4210 - 3330
40x=88040x = 880
x=88040x = \frac{880}{40}
x=22x = 22
Now, substitute the value of xx back into the equation for yy:
y=3722y = 37 - 22
y=15y = 15
So, there were 22 heavy equipment operators and 15 general laborers.

3. Final Answer

The number of heavy equipment operators hired was
2

2. The number of general laborers hired was 15.

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